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Three point charges of each of charge q are placed on three vertices of a square of side "l" meter . Find the magnitude of electric field at the centre of the square .


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  • The SI unit of quantity of electric charge is the coulomb, which is equivalent to about $6.242 \times 10^{18}$ e (e is the charge of a proton). Hence, the charge of an electron is approximately $?1.602 \times 10^{?19}$ C.
Answer : (c) $\;\large\frac{2kq}{l^2}$
Explanation : Electric field due to $q_{1}\; and \; q_{3}\;$ is equal and opposite and therefore cancel each other . Net electric field will be due to only $q_{2}\;.$
$Distance\;of\;q_{2}\;from\;O (r)=\large\frac{l}{\sqrt{2}}$
answered Jan 29, 2014 by yamini.v
edited Jan 30, 2014 by yamini.v

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