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The most common oxidation states of Gold are:

$\begin{array}{1 1}(a)\;\text{+I and +II}&(b)\;\text{+II and +III}\\(c)\;\text{+I and +III}&(d)\;\text{+II and +IV}\end{array}$

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Answer: The most common oxidation states of gold are Au(I) and Au(III).
The oxidation state of gold in its compounds ranges from −1 to +5, but Au(I) and Au(III) dominate its chemistry
Au(I), referred to as the aurous ion, is the most common oxidation state with soft ligands such as thioethers, thiolates, and tertiary phosphines.
Au(III) (auric) is a common oxidation state, and is illustrated by gold(III) chloride, $Au_2Cl_6$.
answered Jan 29, 2014 by sreemathi.v
edited Aug 4, 2014 by balaji.thirumalai

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