$(a)\;q_{1}=q_{2}\qquad(b)\;q_{1}=9 q_{2}\qquad(c)\;q_{2}=9 q_{1}\qquad(d)\;none$

Answer : $\;q_{1}=9 q_{2}$

Explanation : $\;\large\frac{kq_{1}}{r^{2}_{1}}=\large\frac{kq_{2}}{r^{2}_{2}}$

$\;\large\frac{kq_{1}}{r^{2}_{1}}=\large\frac{kq_{2}}{r^{2}_{2}}$

Explanation : $\;\large\frac{kq_{1}}{r^{2}_{1}}=\large\frac{kq_{2}}{r^{2}_{2}}$

$\large\frac{kq_{1}}{(\large\frac{3a}{2})^2}=\large\frac{kq_{2}}{(\large\frac{a}{2})^2}$

$\large\frac{q_{1}}{9}=q_{2}$

$q_{1}=9 q_{2}\;.$

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