$(a)\;\large\frac{kq^2}{4}\qquad(b)\;\large\frac{kq^2}{9}\qquad(c)\;\large\frac{kq^2}{36}\qquad(d)\;zero$

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Answer : (c) $\;\large\frac{kq^2}{36}$

Explanation :

$\;Force \;on\;q_{2}=F_{q_{1}}+F_{q_{3}}+F_{q_{4}}$

$F_{net}=\large\frac{kq_{1}q_{2}}{2^2} \hat{i}-\large\frac{kq_{2}q_{3}}{2^2} \hat{i}+\large\frac{kq_{2}q_{4}}{2^2} \hat{(-i)}$

$q_{1}=q_{2}=q_{3}=q_{4}=q$

$F_{net}=-\large\frac{kq^2}{36} \hat{i}\;.$

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