$\begin{array}{1 1} 5.29\;\mu B \\ 6.34 \;\mu B \\ 2.34\;\mu B \\ 7.14\;\mu B \end{array}$

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Answer: 5.29 $\mu_B$

The magnetic moment is related to the number of unpaired electrons $ = \sqrt{n(n+2)} \mu_B$, where $\mu_B$ is the Bohr magneton (and $n$ is the number of unpaired electrons)

Mn (II) has 5 unpaired electrons $\rightarrow [Ar]3d^5$

$\Rightarrow$ Magnetic moment $ = \sqrt {5 \times 7}\; \mu_B = 5.29 \mu_B$

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