Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

Calculate the expected magnetic moment of a salt where Manganese is in the +II state?

$\begin{array}{1 1} 5.29\;\mu B \\ 6.34 \;\mu B \\ 2.34\;\mu B \\ 7.14\;\mu B \end{array}$

Can you answer this question?

1 Answer

0 votes
Answer: 5.29 $\mu_B$
The magnetic moment is related to the number of unpaired electrons $ = \sqrt{n(n+2)} \mu_B$, where $\mu_B$ is the Bohr magneton (and $n$ is the number of unpaired electrons)
Mn (II) has 5 unpaired electrons $\rightarrow [Ar]3d^5$
$\Rightarrow$ Magnetic moment $ = \sqrt {5 \times 7}\; \mu_B = 5.29 \mu_B$
answered Jan 29, 2014 by sreemathi.v
edited Aug 4, 2014 by balaji.thirumalai

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App