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# Calculate the expected magnetic moment of a salt where Manganese is in the +II state?

$\begin{array}{1 1} 5.29\;\mu B \\ 6.34 \;\mu B \\ 2.34\;\mu B \\ 7.14\;\mu B \end{array}$

Answer: 5.29 $\mu_B$
The magnetic moment is related to the number of unpaired electrons $= \sqrt{n(n+2)} \mu_B$, where $\mu_B$ is the Bohr magneton (and $n$ is the number of unpaired electrons)
Mn (II) has 5 unpaired electrons $\rightarrow [Ar]3d^5$
$\Rightarrow$ Magnetic moment $= \sqrt {5 \times 7}\; \mu_B = 5.29 \mu_B$
edited Aug 4, 2014