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Arrange La$^{3+}$, Pm$^{3+}$, Yb$^{3+}$ and Ce$^{3+}$ in order of increasing ionic radii

$\begin{array}{1 1}La^{3+} < Pm^{3+} < Yb^{3+} < Ce^{3+} \\Pm^{3+} < La^{3+} < Yb^{3+} < Ce^{3+} \\ Yb^{3+} < Pm^{3+} < Ce^{3+} < La^{3+} \\ Yb^{3+} < Ce^{3+} < Pm^{3+} < La^{3+}\end{array}$

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Answer: Yb$^{3+}$ < Pm$^{3+}$ < Ce$^{3+}$ < La$^{3+}$
The ionic size decreases from La$^{3+}$ to Lu$^{3+}$ due to Lanthanide contraction.
The values for the given elements are as follows:
$\begin{array} {lllll} & Yb^{3+} & Pm^{3+} & Ce^{3+} &La^{3+}\\ \text{Ionic Radii (pm)} & 86 & 98 &103 &106 \end{array}$
answered Jan 29, 2014 by sreemathi.v
edited Aug 5, 2014 by balaji.thirumalai
 

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