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For the given elements and their atomic numbers, which of these have the highest second ionization enthalpy?

$\begin{array} {lllll} & V & Cr & Mn & Fe \\ \text{Atomic Numbers} & 23 & 24 & 25 & 26 \end{array}$

$\begin{array}{1 1} V \\ Mn \\ Fe \\ Cr \end{array}$

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Answer: Cr
The second ionization potential for Cr (and Cu) are larger than their neighbouring elements. The electronic configuration of Cr$^{+}$ is $3d^5$ (half-filled). For the second ionization potential, the electron is to be removed from very stable configurations.
answered Jan 29, 2014 by sreemathi.v
edited Aug 5, 2014 by balaji.thirumalai

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