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In lanthanides the differentiating electron enters into

$\begin{array}{1 1}(a)\;\text{d-subshell}&(b)\;\text{f-subshell}\\(c)\;\text{p-subshell}&(d)\;\text{s-subshell}\end{array}$

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Answer: in lanthanides the differentiating electron enters into f-subshell
In Lanthanides, the last or differentiating electron enters into 4f orbital of the anti-penultimate shell, which lies two quantum levels lower than valence shell.
Hence the series of 14 elements in lanthanoids is called as 4f series
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