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In lanthanides the differentiating electron enters into

$\begin{array}{1 1}(a)\;\text{d-subshell}&(b)\;\text{f-subshell}\\(c)\;\text{p-subshell}&(d)\;\text{s-subshell}\end{array}$

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Answer: in lanthanides the differentiating electron enters into f-subshell
In Lanthanides, the last or differentiating electron enters into 4f orbital of the anti-penultimate shell, which lies two quantum levels lower than valence shell.
Hence the series of 14 elements in lanthanoids is called as 4f series
answered Jan 29, 2014 by sreemathi.v
edited Aug 5, 2014 by balaji.thirumalai
 

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