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What happens when a solution of potassium chromate is treated with excess dil. Nitric acid?

$\begin{array}{1 1} Cr^{3+}\; and Cr_2O_7^{2-}\; are\; formed \\ Cr_2O_7^{2-}\; and\; H_2O\; are\; formed \\ CrO_4^{2-}\; is\; reduced \;to\; +3\; state\; of\; Cr \\ CrO_4^{2-} is\; reduced\; to\; +7\; state\; of\; Cr \end{array}$

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Answer: Cr$_2$O$_7^{2-}$ and H$_2$O are formed
Dil. Nitric acid converts chromate to dichromate and water.
2K$_2$CrO$_4$ + 2HNO$_3 \rightarrow$ K$_2$Cr$_2$O$_7$ + 2KNO$_3$ + H$_2$O
$\Rightarrow$ 2CrO$_4^{-2} \overset{H^{+}}\rightleftharpoons$ Cr$_2$O$_7^{2-}$ + H$_2$O
answered Jan 29, 2014 by sreemathi.v
edited Aug 5, 2014 by balaji.thirumalai

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