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Home  >>  JEEMAIN and NEET  >>  Mathematics  >>  Class11  >>  Statistics

If the coefficient of variation of a distribution is 45% and the mean is 12 then its standard deviation is

$\begin {array} {1 1} (A)\;5.2 & \quad (B)\;5.3 \\ (C)\;5.4 & \quad (D)\;None\; of \: these \end {array}$

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1 Answer

Since, percentage of coefficient of variation
$ = \large\frac{Standard\: deviation }{Mean} $ $ \times 100$
$ \therefore 45 = \large\frac{\sigma}{12}$ $ \times 100$
$ \sigma = \large\frac{45 \times 12}{100}$
$ = 5.4$
Ans : (C)
answered Jan 29, 2014 by thanvigandhi_1
 

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