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# If the coefficient of variation of a distribution is 45% and the mean is 12 then its standard deviation is

$\begin {array} {1 1} (A)\;5.2 & \quad (B)\;5.3 \\ (C)\;5.4 & \quad (D)\;None\; of \: these \end {array}$

$= \large\frac{Standard\: deviation }{Mean}$ $\times 100$
$\therefore 45 = \large\frac{\sigma}{12}$ $\times 100$
$\sigma = \large\frac{45 \times 12}{100}$
$= 5.4$