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Home  >>  JEEMAIN and AIPMT  >>  Mathematics  >>  Class11  >>  Statistics
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The variance of 6, 8, 10, 12, 14 is

$\begin {array} {1 1} (A)\;1 & \quad (B)\;8 \\ (C)\;12 & \quad (D)\;16 \end {array}$

Can you answer this question?
 
 

1 Answer

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Mean $ = \overline x = \large\frac{6+8+10+12+14}{5}$
$ = \large\frac{50}{5}$
$ = 10$
$ \sigma^2=\large\frac{ \Sigma (x-M)^2}{n}$
$ \sigma^2=8$
Ans : (B)
answered Jan 29, 2014 by thanvigandhi_1
 
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