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A ring of radius R is having charges $\; q \;and \; 3 q\;$ distributed on its two half parts . The electric potential at a point on the axis $\;\sqrt{3}\;R\;$ from its centre is


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Answer : (b) $\;\large\frac{2\;k\;q}{R}$
Explanation : Every point on ring is at a same distance from p
$V=\large\frac{k\;q}{2 R}+\large\frac{k\;3\;q}{2R}=\large\frac{2\;k\;q}{R}\;.$
answered Jan 30, 2014 by yamini.v
edited Jan 31, 2014 by yamini.v

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