logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
0 votes

The radius of (Atomic number of La = 57) is 1.06 A. Which one of the following given values will be closest to the radius of Lu$^{3+}$? Note: Atomic radius of Lu = 71.

$\begin{array}{1 1}(a)\;Cr^{+3},Fe^{+3}&(b)\;Fe^{+3},Mn^{+2}\\(c)\;Fe^{+3},CO^{+3}&(d)\;Sc^{+3},Cr^{+3}\end{array}$

Can you answer this question?
 
 

1 Answer

0 votes
Answer: 0.85 A
The ionic radii of Ln$^{3+}$ reduces from La$^{3+}$ to Lu$^{3+}$ due to Lanthanide Contraction.
Therefore the lowest value here must be the one closest ionic radii of Lu$^{3+} \rightarrow$ 0.85 A.
answered Jan 30, 2014 by sreemathi.v
edited Aug 5, 2014 by balaji.thirumalai
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...