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The radius of (Atomic number of La = 57) is 1.06 A. Which one of the following given values will be closest to the radius of Lu$^{3+}$? Note: Atomic radius of Lu = 71.

$\begin{array}{1 1}(a)\;Cr^{+3},Fe^{+3}&(b)\;Fe^{+3},Mn^{+2}\\(c)\;Fe^{+3},CO^{+3}&(d)\;Sc^{+3},Cr^{+3}\end{array}$

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Answer: 0.85 A
The ionic radii of Ln$^{3+}$ reduces from La$^{3+}$ to Lu$^{3+}$ due to Lanthanide Contraction.
Therefore the lowest value here must be the one closest ionic radii of Lu$^{3+} \rightarrow$ 0.85 A.
answered Jan 30, 2014 by sreemathi.v
edited Aug 5, 2014 by balaji.thirumalai

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