logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
0 votes

The Atomic numbers of Mn, Fe and Co are 25, 26 and 27 respectively. The order of Magnetic moments among the following is

$(a)\; [MnCl_4]^{2-} \rightarrow [Fe(CN)_6]^{4-} \rightarrow [CoCl_4]^{2-}$ $(b)\; [Fe(CN)_6]^{4-}\rightarrow [MnCl_4]^{2-}\rightarrow [CoCl_4]^{2-}$ $(c)\; [MnCl_4]^{2-} \rightarrow[CoCl_4]^{2-} \rightarrow [Fe(CN)_6]^{4-} $ $(d)\; [Fe(CN)_6]^{4-}\rightarrow [CoCl_4]^{2-} \rightarrow [MnCl_4]^{2-}$
Can you answer this question?
 
 

1 Answer

0 votes
Answer: $ [MnCl_4]^{2-} \rightarrow[CoCl_4]^{2-} \rightarrow [Fe(CN)_6]^{4-} $
$Mn^{2+}$, $Co^{2+}$ and $Fe^{2+}$ have 5, 3 and 0 unpaired electrons respectively, therefore the correct order is $ [MnCl_4]^{2-} \rightarrow[CoCl_4]^{2-} \rightarrow [Fe(CN)_6]^{4-} $
answered Jan 30, 2014 by sreemathi.v
edited Aug 5, 2014 by balaji.thirumalai
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...