Browse Questions

# Consider the situation of figure the work done in moving to particles from P to A is $\;W_{A}\;is\;W_{B}\;$ and $\;P\;to\;C\;W_{C}\;$ Find the correct relation .

$(a)\;W_{A} < W_{B} < W_{C}\qquad(b)\;W_{A} > W_{B} > W_{C}\qquad(c)\;W_{A} = W_{B} = W_{C}\qquad(d)\;None$

Answer : (c) $\;W_{A} = W_{B} = W_{C}$
Explanation : $W_{A}=-P\;.E_{P} + P\;.E_{A}$
$P\;.E_{A}=P\;.E_{B} = P\;.E_{C}$
$Therefore\;W_{A} =W_{B} = W_{C}\;.$