logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
Home  >>  CBSE XII  >>  Math  >>  Vector Algebra
0 votes

What is the angle between following planes $2x-3y+4z=1$ and $-x+y=4$?

Can you answer this question?
 
 

1 Answer

0 votes
Toolbox:
  • The angle between two planes is the angle between the normals to the two planes. $ \theta=\cos^{-1}\bigg( \large\frac{\overrightarrow n_1.\overrightarrow n_2}{|\overrightarrow n_1||\overrightarrow n_2|} \bigg).$ If $ \overrightarrow n_1.\overrightarrow n_2=0$ the planes are at right angles.
$ 2x-3y+4z=1$ (i) and $-x+y=4$ (ii)
$ \overrightarrow n_1 = 2\overrightarrow i-3\overrightarrow j+4\overrightarrow k \: \: \overrightarrow n_2=-\overrightarrow i+\overrightarrow j$
$ \theta = \cos^{-1} \large\frac{[\overrightarrow n_1.\overrightarrow n_2]}{|\overrightarrow n_1||\overrightarrow n_2|}$$=\cos^{-1} \bigg[ \large\frac{(2)(-1)+(-3)(1)+0}{\sqrt{4+9+16}\sqrt{1+1}} \bigg]$
$ = \cos^{-1} \large\frac{-5}{\sqrt{58}}$
answered Jan 30, 2014 by balaji
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...