logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
0 votes

What is the spin only magnetic moment value in (Bohr Magneton units) of Cr(CO)$_6$?

$\begin {array} {1 1} 0 \\ 2.84 \\ 4.90 \\ 5.92 \end {array}$

Can you answer this question?
 
 

1 Answer

0 votes
Answer: 0
The electron configuration is $[Ar]3d^54s^1$.We have to accomodate the 6 Ligands and the fact that CO is a strong ligand.
This results in $d^2sp^3$ hybridization. Therefore, there are no unpaired electrons in $Cr(CO)_6$. Hence $n = 0$
And the spin only magnetic moment is also 0.
answered Jan 30, 2014 by sreemathi.v
edited Aug 5, 2014 by balaji.thirumalai
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...