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The electric field in a region of space is $\;\overrightarrow{E}=5 \hat{i} +3 \hat {j}\;.$ The flux of $\;\overrightarrow{E}\;$ due to this field through an area $\;1 m^2\;$ lying in x - z plane is

$(a)\;5\qquad(b)\;10\qquad(c)\;3\qquad(d)\;3 \sqrt{34}$

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Answer : (c) 3
Explanation :
$\phi=\oint\;\overrightarrow{E}\;.\overrightarrow{da}$
$\phi=\oint\;(5 \hat{i}+3 \hat{j})\;.(d a \hat{j})$
$\phi = \oint 3 d a=3\times1$
$\phi=3\;N - m^2\;.$
answered Jan 30, 2014 by yamini.v
 

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