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Calculate the magnitude of an electric field which can just balance a deutron of mass $\;3.2\times10^{-27}\;kg$

$(a)\;2\times10^{-5}\;N/C\qquad(b)\;2\times10^{-7}\;N/C\qquad(c)\;3\times10^{-7}\;N/C\qquad(d)\;2\times10^{-6}\;N/C$

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Answer : (b) $\;2\times10^{-7}\;N/C$
Explanation : $E\;q = mg$
$E\times1.6\times10^{-19} = 3.2 \times 10^{-27}\times10$
$E=2\times10^{-7}\;N/C\;.$
answered Jan 30, 2014 by yamini.v
 

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