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# The equivalent weight of potassium permanganate for acid solution is

$(a)\;158\qquad(b)\;52.16\qquad(c)\;31.6\qquad(d)\;79$

Equivalent weight of $KMnO_4$ in acidic medium is $M/5$
Equivalent weight = $\large\frac{158}{5 }$$= 31.6$
Hence (c) is the correct answer.