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On moving a charge of 100 coulombs by 10 cm , 5 J of work is done , then the potential difference between the points is

$(a)\;0.1 V\qquad(b)\;0.2 V\qquad(c)\;0.05 V\qquad(d)\;0.5 V$

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Answer : (c) 0.05 V
Explanation : Work done = $\;\Delta P\;.E$
$5=q\;\Delta V$
$5=100\;\Delta V$
$=\Delta V = 0.05 V\;.$
answered Jan 30, 2014 by yamini.v
 

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