# On moving a charge of 100 coulombs by 10 cm , 5 J of work is done , then the potential difference between the points is

$(a)\;0.1 V\qquad(b)\;0.2 V\qquad(c)\;0.05 V\qquad(d)\;0.5 V$

Explanation : Work done = $\;\Delta P\;.E$
$5=q\;\Delta V$
$5=100\;\Delta V$
$=\Delta V = 0.05 V\;.$