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Electric field and potential inside hollow charged conducting sphere are respectively

$(a)\; (0 ,0)\qquad(b)\;(0 , \large\frac{k \;q}{r})\qquad(c)\;(\large\frac{k\;q}{r^2} , 0)\qquad(d)\;(\large\frac{k\;q}{r^2},\large\frac{k\;q}{r})$

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Answer : $\;(0 , \large\frac{k \;q}{r})$
Explanation :
Fielf inside a conducting sphere is zero and potential being constant is equal to potential at the surface of hollow sphere .
answered Jan 30, 2014 by yamini.v
 

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