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A $\;Q \;\mu C\;$ is placed at the centre of a cube. The flux coming from any surface will be

$(a)\;\large\frac{Q}{6 \in_{0}}\times10^{-6}\qquad(b)\;\large\frac{Q}{6\in_{0}}\times10^{-3} \qquad(c)\;\large\frac{Q}{24 \in_{0}}\qquad(d)\;\large\frac{Q}{8 \in_{0}}$

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Answer : (a) $\;\large\frac{Q}{6\in_{0}}\times10^{-6}$
Explanation : Flux through every surface will be equal let it be x
$Total\;flux = 6x = \large\frac{Q}{\in_{0}}\times10^{-6}$
$x=\large\frac{Q}{6 \in_{0}}\times10^{-6}\;.$
answered Jan 30, 2014 by yamini.v

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