Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

The figure shows two capacitors of capacitance c and charged to same potential c connected in two circuits . What will be the charge on the capacitor after a time $t= cr$ from the start


$(a)\;vc/e, vc \\ (b)\;vc,vc \\ (c)\;vc,vc/e \\ (d)\;vc/e,vc/e $
Can you answer this question?

1 Answer

0 votes
In 1st case the diode is connected in forward bias and so current flows.
If Q is initial charge on the capacitor the charge reduces to Q/e in time $t= CR$
But $Q= VC$
$\therefore\; Q_t$, charge after time $t =\large\frac{Vc}{e}$
In the second case the diode is connected in reversed bias and so no current flows and the charge in the capacitor remains same ie $Q= VC$
Hence a is the correct answer.
answered Jan 30, 2014 by meena.p

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App