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Metallic sphere of radius R is charged to potential V . The charge q is proportional to

$(a)\;V \qquad(b)\;R \qquad(c)\;Both \; V\;and\; R\qquad(d)\;None$

1 Answer

Answer : (c) Both V and R
Explanation : Potential of metallic sphere is constant and equal to potential on surface
$Therefore$
$V=\large\frac{k\;q}{R}$
$q=\large\frac{VR}{k}$
Hence q is proportional to both V & R .
answered Jan 30, 2014 by yamini.v
 

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