Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

An electric dipole of moment $\;\overrightarrow{P}\;$ is lying along a uniform electric field $\;\overrightarrow{E}\;$ The work done in relating the dipole by $\;90^{0}\;is$

$(a)\;PE\qquad(b)\;\sqrt{2} PE\qquad(c)\;\large\frac{PE}{2}\qquad(d)\;2PE$

Can you answer this question?

1 Answer

0 votes
Answer : (a) PE
Explanation :
Work done = $\Delta P .E$
$P . E = -\overrightarrow{P} . \overrightarrow{E}$
$P . E_{f}=0$
$P . E_{i} = -P E$
$\Delta P . E=P E=work done\;. $
answered Jan 30, 2014 by yamini.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App