Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

If there are n capacitors in parallel connected to V volt source , then energy stored is equal to

$(a)\;C V\qquad(b)\;C V ^2\qquad(c)\;\large\frac{1}{2n}\;C V^2\qquad(d)\;\large\frac{1}{2}\;n\;C V^2$

Can you answer this question?

1 Answer

0 votes
Answer : (d) $\;\large\frac{1}{2}\;n\;C V^2$
Explanation : Each capacitor has voltage difference = V
Number of capacitors = n
Total energy = $\;n\times\;$ energy across one capacitor
$=\large\frac{1}{2}\;n\;C V^2\;.$
answered Jan 30, 2014 by yamini.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App