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# In the circuit given below if the output $D=1$ the input must be

$(a)\;A=0\;B=1\;C=0 \\ (b)\;A=0\;B=0\;C=1 \\ (c)\; A=1\;B=0\;C=1\\ (d)\;A=1\;B=0\;C=0$

$D=(A+B).C$
So we get $D=1$ for $A=1,B=0,C=1$