Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

What is the principal quantum no. of H-atom Orbital if the electron energy is -3.4 eV ? also report the angular momentum of electron


Can you answer this question?

1 Answer

0 votes
$E_1 for H = -13.6 eV$
$E_n = \large\frac{E_1}{E_2}$
= -3.4 = $\large\frac{-13.6}{n^2}$
n = 2
Now Angular momentum (mur) = $\large\frac{n.h}{2\pi}$
$= \large\frac{2\times6.626\times10^{-34}} {2\times3.14}$
Hence answer is (a)
answered Jan 31, 2014 by sharmaaparna1

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App