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Find out the energy of H atom in first excitation state. The value of permitivity factor $4\pi E_{\large\circ} = 1.11264\times10^{-10} C^2N^{-1}m{-2}$

$(a)\;2.443\times10^{-19}J\qquad(b)\;5.443\times10^{-19}J\qquad(c)\;5.443\times10^{-10}J\qquad(d)\;3.432\times10^{-19}J$

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