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The effective atomic number of Cr in $[Cr(NH_3)_6]Cl_3$ is

$(a)\;35\qquad(b)\;27\qquad(c)\;33\qquad(d)\;36$

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The effective atomic number of Cr in $[Cr(NH_3)_6]Cl_3$ is 33.
Hence (b) is the correct answer.
answered Jan 31, 2014 by sreemathi.v
 
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