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In the coordination compound,$K_4[Ni(CN)_4]$ the oxidation state of nickel is

$(a)\;0\qquad(b)\;+1\qquad(c)\;+2\qquad(d)\;-1$

1 Answer

In the coordination compound,$K_4[Ni(CN)_4]$ the oxidation state of nickel is 0.
Hence (a) is the correct answer.
answered Jan 31, 2014 by sreemathi.v
 
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