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# The correct order of magnetic moments (spin only values in B.M) among is

$\begin{array}{1 1}(a)\;MnCl_4^{2-} > COCl_4^{2-} > Fe(CN)_6^{-4}&(b)\;Fe(CN)_6^{-4} > MnCl_4^{2-} > COCl_4^{2-}\\(c)\;Fe(CN)_6^{-4} > COCl_4^{2-} > MnCl_4^{2-}&(d)\;MnCl_4^{2-} > Fe(CN)_6^{-4} > COCl_4^{2-} \end{array}$

$MnCl_4^{2-} > COCl_4^{2-} > Fe(CN)_6^{-4}$
Hence (a) is the correct answer.