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The oxidation state of Cr in the complex $[Cr(NH_3)_4Cl_2]^+$ is

$(a)\;+3\qquad(b)\;+2\qquad(c)\;+1\qquad(d)\;0$

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The oxidation state of Cr in the complex $[Cr(NH_3)_4Cl_2]^+$ is +3.
Hence (a) is the correct answer.
answered Jan 31, 2014 by sreemathi.v
 
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Tag:MathPhyChemBioOther
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