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Calomol $(Hg_2Cl_2)$ on reaction with ammonium hydroxide gives

$(a)\;HgNH_2Cl\qquad(b)\;NH_2-Hg-Hg-Cl\qquad(c)\;Hg_2O\qquad(d)\;HgO$

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Calomol $(Hg_2Cl_2)$ on reaction with ammonium hydroxide gives $HgNH_2Cl$
Hence (a) is the correct answer.
answered Jan 31, 2014 by sreemathi.v
 

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