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Home  >>  JEEMAIN and NEET  >>  Physics  >>  Class11  >>  Kinetic Theory of Gases

Gas-A is kept in the left partition of the container with a temperature of T at pressure 2P. Gas-B is kept in the right part of the container with a temperature of 4T at pressure P. When what is the value of the Pressure P' when the partition is removed?

(A) P (B) 8/27 P (C) 27/8 P (D) 3P

1 Answer

For gas A, $n_A = \large\frac{2P \times V}{RT}$ and $n_B = \large\frac{P \times V}{4RT}$
After oprning the partition, $n_A + n_B = \large \frac{9P}{4RT}$
$n = n_A + n_B = \large\frac{2P'V}{3RT}$$ =\large \frac{9P}{4RT}$
$\Rightarrow P' = \large\frac{27P}{8}$
answered Jan 31, 2014 by balaji
edited Jan 31, 2014 by balaji
 

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