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Home  >>  JEEMAIN and AIPMT  >>  Mathematics  >>  Class11  >>  Statistics
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$cov (x,y) $ if $ \Sigma x = 55\: \Sigma y = 82\: \Sigma xy = 565\: n=8$ is

$\begin {array} {1 1} (A)\;0.16 & \quad (B)\;0.7 \\ (C)\;7 & \quad (D)\;6 \end {array}$

Can you answer this question?
 
 

1 Answer

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$ cov (x,y) = \large\frac{n \Sigma xy - ( \Sigma x ) ( \Sigma y)}{n^2}$
$ = \large\frac{8(565)-(55)(82)}{8 \times 8}$
$ = \large\frac{4520-4510}{64}$
$ = \large\frac{10}{64}$
$ = 0.16$
Ans : (A)
answered Feb 1, 2014 by thanvigandhi_1
 

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