# Karl - Pearson's coefficient of Skewness of a distribution is $0.4$ If SD is 6 and mean 40, then median of the distribution is

$\begin {array} {1 1} (A)\;39.5 & \quad (B)\;39 \\ (C)\;39.2 & \quad (D)\;None \: of \: these \end {array}$

## 1 Answer

Toolbox:
• Coefficient of skewness = $\large\frac{3(mean - median )}{SD}$
Coefficient of skewness = $\large\frac{3(mean - median )}{SD}$
$\Rightarrow\: 0.4 = \large\frac{3(40-M_e)}{6}$
$2.4 = 120-3\: M_e$
$3\: M_e = 117.6$
$M_e = 39.2$
Ans : (C)
answered Feb 1, 2014
edited Mar 26, 2014

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