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Home  >>  CBSE XII  >>  Math  >>  Model Papers
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Using principal value, calculate the following : \( \sin^{-1} \bigg( \sin \large\frac{3\pi}{5} \bigg). \)

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\[Sin^{-1}sin(\pi-\frac{2\pi}{5})=Sin^{-1}sin\frac{2\pi}{5}=\frac{2\pi}{5}\]
answered Feb 16, 2013 by rvidyagovindarajan_1
 
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