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When borax is heated in a platinum loop, the transparent bead formed contains

(a) $Na_2Br_4O_7$
(b) Sodium metaborate + $B_2O_3$
(c) Water
(d) CaO
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Answer: Sodium metaborate + $B_2O_3$
$Na_2B_4O_7.10H_2O$ (Borax) $\xrightarrow[Pt. loop]{\Delta} 2NaBO_2$ (Sodium metaborate) $+ B_2O_3$ (Boric anhydride)
answered Feb 1, 2014 by mosymeow_1
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