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A test tube containing a nitrate and another containing a bromide and $MnO_2$ are treated with conc. $H_2SO_4$. The brown fumes evolved are passed through water. The water will be coloured by

(a) the nitrate
(b) the bromide
(c) both nitrate and bromide
(d) none of the two
Can you answer this question?

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Answer: the bromide
$NO^-_3$ gives $NO_3$ with conc. $H_2SO_4$ which on pasing through water form colourless $HNO_3$.
$Br^- + MnO_3$ on heating with conc. $H_2SO_4$ gives $Br_2$ gas which on passing through water imparts a brown colour.
answered Feb 1, 2014 by mosymeow_1

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