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Heating of oxalic acid with conc. $H_2SO_4$ gives

(a) $CO$
(b) $CO_2$
(c) $CO + CO_2$
(d) None of these
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Answer: $CO + CO_2$
$H_2C_2O_4$(oxalic acid)$ \xrightarrow[\Delta]{conc. H_2SO_4} H_2O + CO$ (carbon monoxide) $+ CO_2 \uparrow$ (carbon dioxide)
answered Feb 1, 2014 by mosymeow_1
edited Feb 1, 2014 by mosymeow_1

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