info@clay6.com
+91-9566306857
(9am to 6pm)
logo

Ask Questions, Get Answers

X
Want help in doing your homework? We will solve it for you. Click to know more.
 

Acidified $K_2Cr_2O_7$ turns green by

(a) $SO_2$
(b) $CO$
(c) $SiO_2$
(d) $HCl$

1 Answer

Need homework help? Click here.
Answer: $SO_2$
$K_2Cr_2O_7$ turns green by $SO_2$ due to its reduction.
$K_2Cr_2O_7 + H_2SO_4 + 3SO_2 \longrightarrow K_2SO_4 + Cr_2(SO_4)_3 $(Green)$ + H_2O$
answered Feb 1, 2014 by mosymeow_1
 
...