info@clay6.com
logo

Ask Questions, Get Answers

X
 
Answer
Comment
Share
Q)

Acidified $K_2Cr_2O_7$ turns green by

(a) $SO_2$
(b) $CO$
(c) $SiO_2$
(d) $HCl$

1 Answer

Comment
A)
Need homework help? Click here.
Answer: $SO_2$
$K_2Cr_2O_7$ turns green by $SO_2$ due to its reduction.
$K_2Cr_2O_7 + H_2SO_4 + 3SO_2 \longrightarrow K_2SO_4 + Cr_2(SO_4)_3 $(Green)$ + H_2O$
Home Ask Homework Questions
...