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$H_2S$ and $SO_2$ can be distinguished by

(a) Litmus paper
(b) Lime water
(c) $Pb(CH_3COO)_2$
(d) $HCl$

1 Answer

Answer: $Pb(CH_3COO)_2$
 
$Pb(CH_3COO)_2 + H_2S \longrightarrow PbS + 2CH_3COOH$
$SO_2$ has no effect on $Pb(CH_3COO)_2$.
answered Feb 1, 2014 by mosymeow_1
 
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