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Consider the coordination compound,$Na_2[Pt(CN)_4]$.The Lewis acid is

$(a)\;[Pt(CN)_4]^{2-}\qquad(b)\;Na^+\qquad(c)\;Pt\qquad(d)\;Pt^{2+}$

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The Lewis acid is $Pt^{2+}$
Hence (d) is the correct answer.
answered Feb 3, 2014 by sreemathi.v
 

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