logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
0 votes

The electric field in a region is given by $\;\overrightarrow{E}=\alpha \hat{i}+\beta \hat{j}\;.$ Here $\;\alpha\; and \; \beta\;$ are constants . The net flux through a square are of side l parallel to y - z plane

$(a)\;\alpha\;l^2\qquad(b)\;\beta\;l^2\qquad(c)\;(\alpha+\beta)\;l^2\qquad(d)\;\large\frac{\alpha+\beta}{2}\;l^2$

Can you answer this question?
 
 

1 Answer

0 votes
Answer : (a) $\;\alpha\;l^2$
Explanation : A square are of side l parallel to y - z plane in vector form can be written as
$\overrightarrow{S}=l^2\;\hat{i}$
$\overrightarrow{E}=\alpha \hat{i}+\beta \hat{j}$
$\phi=\overrightarrow{E}\;.\overrightarrow{S}$
$\phi=(\alpha \hat{i}+\beta\hat{j})\;.(l^2\;.\hat{i})$
$\phi=\alpha\;l^2\;.$
answered Feb 3, 2014 by yamini.v
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...