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Home  >>  JEEMAIN and NEET  >>  Mathematics  >>  Class12  >>  Differential Equations

Find the degree of the following differential equation $\bigg(\large\frac{d^2 y}{dx^2}\bigg)^{1/2} =\bigg( \large\frac{dy}{dx}+3\bigg)^{1/3}$

$(a)\;\frac{1}{2} \\ (b)\;2 \\ (c)\;6 \\ (d)\;3 $

1 Answer

$\bigg(\large\frac{d^2 y}{dx}\bigg) ^{6/2} =\bigg( \large\frac{dy}{dx} $$+3\bigg)^{6/3}$
$\bigg(\large\frac{d^2 y}{dx}\bigg) ^3 =\bigg( \large\frac{dy}{dx} $$+3\bigg)^2$
Free from radical and fraction
Hence d is the correct answer.
answered Feb 3, 2014 by meena.p
 

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