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Consider the charging of a capacitor. Let $Q_1$ be the charge given to it in first t seconds and $Q_2$ be the charge given to it in the next t seconds. Also, let $t_1$ be the time required to deposit a charge Q (less than half the maximum charge) and $t_2$ be the time required to deposit an additional charge of Q, then:

$\begin {array} {1 1} (A)\;Q_1 > Q_2 , t_1 > t_2 & \quad (B)\;Q_1 > Q_2 , t_1 < t_2 \\ (C)\;Q_1 < Q_2 , t_1 > t_2 & \quad (D)\;Q_1 < Q_2 , t_1 < t_2 \end {array}$

 

1 Answer

The charge to time graph of a capacitor is an exponentially decaying one.
So charge deposited in a fixed interval of time keeps on decreasing.
Also, by the same logic, more amount of time is required to
deposit a fixed amount of charge.
Ans : (B)
answered Feb 3, 2014 by thanvigandhi_1
 

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