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# The probability that at least one of the two events A and B occurs is 0.6.If A and B occur simultaneously with probability 0.3,evaluate $P(\bar{A})+P(\bar{B})$.

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">P($$\ Toolbox: • P(at least one of A and B occeure)=P(A\(\cup$$B)                 $$Also\;\overline{A\cup\;B}=\bar{A}\cap\;\bar{B}$$
• P(simultuneous occurance of AandB)=P(A$$\cap$$B)           $$Also\;\overline{A\cap\;B}=\bar{A}\cup\;\bar{B}$$
P(A$$\cap$$B)=0.6
P($$\overline{A\cup\;B}$$)=1-0.6=0.4
P($$\bar{A}$$$$\cap$$$$\bar{B}$$)=0.4
P(A$$\cap$$B)=0,3
P($$\overline{A\cap\;B}$$)=1-0.3=0.7
P($$\bar{A}\cup$$$$\bar{B}$$)=P($$\bar{A}$$)+P($$\bar{B}$$)-P($$\bar{A}$$$$\cap$$$$\bar{B}$$)
0.7=P($$\bar{A}$$)+P($$\bar{B}$$)-0.4
P($$\bar{A}$$)+P($$\bar{B}$$)=1.2